9x^2+1-6x-3x(x-3)-7x=2x(3x-2)

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Solution for 9x^2+1-6x-3x(x-3)-7x=2x(3x-2) equation: 



9x^2+1-6x-3x(x-3)-7x=2x(3x-2)

We move all terms to the left:

9x^2+1-6x-3x(x-3)-7x-(2x(3x-2))=0

We add all the numbers together, and all the variables

9x^2-13x-3x(x-3)-(2x(3x-2))+1=0

We multiply parentheses

9x^2-3x^2-13x+9x-(2x(3x-2))+1=0



We calculate terms in parentheses: -(2x(3x-2)), so:

2x(3x-2)

We multiply parentheses

6x^2-4x

Back to the equation:

-(6x^2-4x)



We add all the numbers together, and all the variables

6x^2-4x-(6x^2-4x)+1=0

We get rid of parentheses

6x^2-6x^2-4x+4x+1=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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